List Practice in Pyhton

In [1]:

name='superb'
for ch in name: 
   print(ch,'-',end='')

s -u -p -e -r -b -

In [3]:

s=input("enter string ")
print("the string in reverse")
l=len(s)
for a in range(-1 ,(-l-1),-1):
    print(s[a],end=' ')

enter string navodaya
the string in reverse
a y a d o v a n 

In [4]:

s=input("enter string ")
l=len(s)
i=0
for a in range(-1 ,(-l-1),-1):
    print(s[i],"\t",s[a])
    i+=1

enter string school
s 	 l
c 	 o
h 	 o
o 	 h
o 	 c
l 	 s

In [2]:

'a' in 'heya'

Out[2]:

True

In [3]:

'jap' in 'japan'

Out[3]:

True

In [6]:

'paj' not in 'japan'

Out[6]:

True

In [4]:

ord('a')

Out[4]:

97

In [5]:

ord('A')

Out[5]:

65

In [6]:

ord('1')

Out[6]:

49

In [12]:

word='amazing'

In [7]:

chr(65)

Out[7]:

'A'

In [13]:

word

Out[13]:

'amazing'

In [15]:

word[-5:-1]

Out[15]:

'azin'

In [16]:

word[0:-1]

Out[16]:

'amazin'

In [15]:

w="india"
w[0:]

Out[15]:

'india'

In [17]:

word[0:]

Out[17]:

'amazing'

In [20]:

word[-len(word):5]

Out[20]:

'amazi'

In [21]:

len(word)

Out[21]:

7

In [17]:

Out[17]:

'aidn'

In [24]:

word[0]

Out[24]:

'a'

In [25]:

word[-1]

Out[25]:

'g'

In [26]:

s1='spam'
s2='ni'
print("hello,"+s2)
print(3*s1+2*s2)
print(s1[1])

hello,ni
spamspamspamnini
p

In [18]:

s=input("enter string")
l=len(s)
c=0
for i in range(l):
    if s[i]in'aeiou':
        c+=1
        
        
print("number of vowelis  ",c)

enter stringnavodaya
number of vowelis   4

In [25]:

s="india is my country"
t=s.split()
print(s)
print(t)
print(len(s),len(t))

india is my country
['india', 'is', 'my', 'country']
19 4

In [29]:

'apple'>'pineapple'

Out[29]:

False

In [30]:

'ab'>'XY'

Out[30]:

True

In [31]:

'Ax'>'aX'

Out[31]:

False

In [33]:

'apple'in 'pineapple'

Out[33]:

False

In [34]:

'pine' in 'Pineapple'

Out[34]:

False

In [35]:

s='apple'

In [37]:

s[:-1]+s[-1:]

Out[37]:

'apple'

In [38]:

s='#'
p=''
for a in range(5):
    p+=s
    print(p)

#
##
###
####
#####

In [40]:

n=int(input('enter number'))
s='*'*n
for i in range(n):
    print(s)
    s=s[:-1]
    

enter number5
*****
****
***
**
*

In [41]:

sr='kundeshwar'
sr.capitalize()

Out[41]:

'Kundeshwar'

In [43]:

sr.find('d')

Out[43]:

3

In [45]:

sr='--===='
sr.isalnum()

Out[45]:

False

In [46]:

sr.isalpha()

Out[46]:

False

In [48]:

sr.isdigit()

Out[48]:

False

In [49]:

sr.isspace()

Out[49]:

False

In [50]:

sr.isupper()

Out[50]:

False

In [51]:

sr.islower()

Out[51]:

False

In [52]:

sr='hello'
print(sr.lower())
print(sr.upper())

hello
HELLO

In [ ]:

line=input("enter line")
x=line.split()
y=''
for i in range(len(x)):
    x[i]=x[i].upper()
    y+=x[i]
print(y)    

In [ ]:

In [3]:

line=input("enter line")
x=line.split()
y=''
for i in range(len(x)):
    x[i]=x[i].upper()
    y+=' '+x[i]
print(y)

enter linei am your
 I AM YOUR

In [ ]:

s=input("enter phone number with in format stdcode-areacode-number stdcode of 3 digit area code of three digit ad number of 4 digit")
if s[0:4].isdigit():
  print("areacode is right")

In [ ]:

#programt to enter a phone number with 10 digit and two dashes with dashes after area code and next three numbers 
#for example 017-555-1212 is valid 
s=input("enter phone number with in format stdcode-areacode-number stdcode of 3 digit area code of three digit ad number of 4 digit")
if s[0:4].isdigit():
  print("areacode is right")s=input("enter phone number with in format stdcode-areacode-number stdcode of 3 digit area code of three digit ad number of 4 digit")
if len(s)==12 and s[0:3].isdigit() and s[4:7].isdigit() and s[8:].isdigit()and s[3]=='-'and s[7]=='-' :
    print('string is ok')
else:
    print('incorrect string')
    

In [ ]:

#program to enter a string extract all digit from string ,sum all digit in string
#print origianl string ,the digit ,the sum of digit
#if no digit print 'has no digit'
#if input is 'abc123' than output willbe
#print abc123 has the digits 123 which sum to 6
str=input('enter string')
sum=0
dstr=''
for i in range(len(str)):
    if str[i].isdigit():
        sum+=int(str[i])
        dstr+=str[i]
print(str,'has the digits',dstr,'which sum is',sum)

In [ ]:

#program to enter a string extract all digit from string ,sum all digit in string
#print origianl string ,the digit ,the sum of digit
#if no digit print 'has no digit'
#if input is 'abc123' than output willbe
#print abc123 has the digits 123 which sum to 6
str=input('enter string')
sum=0
dstr=''
for i in range(len(str)):
    if str[i].isdigit():
        sum+=int(str[i])
        dstr+=str[i]
print(str,'has the digits',dstr,'which sum is',sum)

In [2]:

#9c3 program to enter a string and print number of word ,character in string
s=input('enter string')
sp=s.split()
cw=len(sp)
cch=len(s)
an=0
print(s,'has number of word',cw,'and number of character',cch)
for i in range(len(s)):
      if s[i].isalnum():
          an+=1
print('number of alphanumeric is ',an,'and its percentage is',(an/cch)*100)

enter stringererew5656--- 23443  234234 fghg
ererew5656--- 23443  234234 fghg has number of word 4 and number of character 32
number of alphanumeric is  25 and its percentage is 78.125

In [ ]:

#9c5 input one integer and one string ,collect digit sequence from string
#then sum digit sequence and integer
n=int(input('enter number'))
s=input('enter a string')
sd=''
for i in range(len(s)):
    if s[i].isnumeric():
        sd+=s[i]
        
print('the sum is ',n+int(sd))

In [ ]:

#9c6 write program to input two string and print small string first then
#print large string in format ex input string is panda python then output will be
#panda
#p        n
# y     o
#   th

s=input('enter first string')
s1=input('enter second string')
ls=len(s)
ls1=len(s1)
if(ls>ls1):
    s,s1=s1,s
    ls,ls1=ls1,ls
print(s)
for i in range(int(ls1/2)+1):
      print(' '*i,s1[i],' '*(ls1-1-2*i),s1[ls1-1-i])